1The graph of y = a(x - h)(x - k) cuts the x-axis at:ax = -h, -kbx = 0, x = hcx = h + kdx = h, x = kShow answer
7If a graph crosses the x-axis at x = -1 and x = 1 and passes through (0, 4), then a is:a4b1c-4d-1Show answer
8If x-intercepts are 1 and 2 and the graph passes through (3, 4), the quadratic function is:ay = -2(x - 1)(x - 2)by = 4(x - 1)(x - 2)cy = (x - 1)(x - 2)dy = 2(x - 1)(x - 2)Show answer
9In y = a(x - h)(x - k), to find a we need:avertexby-intercept onlycone additional pointdx-intercepts onlyShow answer
10If a quadratic graph touches the x-axis at x = -1 and cuts the y-axis at y = -2, its equation is:ay = -2(x + 1)²by = 2(x + 1)²cy = -2(x - 1)²dy = 2(x - 1)²Show answer
11If x-intercepts are -1 and 1 and vertex is (0, -2), the equation is:ay = -2(x - 1)(x + 1)by = 2(x - 1)(x + 1)cy = 2(x + 1)²dy = -2(x + 1)²Show answer
12A function y = f(x) is algebraic if it satisfies a polynomial equation of the form:ay = exby = sin xcPn(x)yn + ... + P0(x) = 0dy = ln xShow answer
15The graph of y = a(x - h)(x - k) meets the x-axis at x = h and x = k. If h = k, the graph:acuts x-axis at two pointsbmeets y-axis onlycdoes not meet x-axisdtouches x-axis at one pointShow answer
19If a quadratic function has x-intercepts x = -2 and x = 1 and passes through (0, 2), then a is:a-2b1c2d-1Show answer